Integrand size = 34, antiderivative size = 114 \[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\frac {\operatorname {AppellF1}\left (1+n,-\frac {1}{2},\frac {1}{2}-m,2+n,\sin (e+f x),-\sin (e+f x)\right ) \sec (e+f x) (d \sin (e+f x))^{1+n} (1+\sin (e+f x))^{\frac {1}{2}-m} (a-a \sin (e+f x)) (a+a \sin (e+f x))^m}{d f (1+n) \sqrt {1-\sin (e+f x)}} \]
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Time = 0.10 (sec) , antiderivative size = 114, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.088, Rules used = {3087, 140, 138} \[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\frac {\sec (e+f x) (a-a \sin (e+f x)) (\sin (e+f x)+1)^{\frac {1}{2}-m} (a \sin (e+f x)+a)^m (d \sin (e+f x))^{n+1} \operatorname {AppellF1}\left (n+1,-\frac {1}{2},\frac {1}{2}-m,n+2,\sin (e+f x),-\sin (e+f x)\right )}{d f (n+1) \sqrt {1-\sin (e+f x)}} \]
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Rule 138
Rule 140
Rule 3087
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sec (e+f x) \sqrt {a-a \sin (e+f x)} \sqrt {a+a \sin (e+f x)}\right ) \text {Subst}\left (\int (d x)^n \sqrt {a-a x} (a+a x)^{-\frac {1}{2}+m} \, dx,x,\sin (e+f x)\right )}{f} \\ & = \frac {\left (\sec (e+f x) (a-a \sin (e+f x)) \sqrt {a+a \sin (e+f x)}\right ) \text {Subst}\left (\int \sqrt {1-x} (d x)^n (a+a x)^{-\frac {1}{2}+m} \, dx,x,\sin (e+f x)\right )}{f \sqrt {1-\sin (e+f x)}} \\ & = \frac {\left (\sec (e+f x) (1+\sin (e+f x))^{\frac {1}{2}-m} (a-a \sin (e+f x)) (a+a \sin (e+f x))^m\right ) \text {Subst}\left (\int \sqrt {1-x} (d x)^n (1+x)^{-\frac {1}{2}+m} \, dx,x,\sin (e+f x)\right )}{f \sqrt {1-\sin (e+f x)}} \\ & = \frac {\operatorname {AppellF1}\left (1+n,-\frac {1}{2},\frac {1}{2}-m,2+n,\sin (e+f x),-\sin (e+f x)\right ) \sec (e+f x) (d \sin (e+f x))^{1+n} (1+\sin (e+f x))^{\frac {1}{2}-m} (a-a \sin (e+f x)) (a+a \sin (e+f x))^m}{d f (1+n) \sqrt {1-\sin (e+f x)}} \\ \end{align*}
\[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx \]
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\[\int \left (d \sin \left (f x +e \right )\right )^{n} \left (a -a \sin \left (f x +e \right )\right ) \left (a +a \sin \left (f x +e \right )\right )^{m}d x\]
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\[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\int { -{\left (a \sin \left (f x + e\right ) - a\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \left (d \sin \left (f x + e\right )\right )^{n} \,d x } \]
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\[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=- a \left (\int \left (- \left (d \sin {\left (e + f x \right )}\right )^{n} \left (a \sin {\left (e + f x \right )} + a\right )^{m}\right )\, dx + \int \left (d \sin {\left (e + f x \right )}\right )^{n} \left (a \sin {\left (e + f x \right )} + a\right )^{m} \sin {\left (e + f x \right )}\, dx\right ) \]
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\[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\int { -{\left (a \sin \left (f x + e\right ) - a\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \left (d \sin \left (f x + e\right )\right )^{n} \,d x } \]
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\[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\int { -{\left (a \sin \left (f x + e\right ) - a\right )} {\left (a \sin \left (f x + e\right ) + a\right )}^{m} \left (d \sin \left (f x + e\right )\right )^{n} \,d x } \]
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Timed out. \[ \int (d \sin (e+f x))^n (a-a \sin (e+f x)) (a+a \sin (e+f x))^m \, dx=\int {\left (d\,\sin \left (e+f\,x\right )\right )}^n\,{\left (a+a\,\sin \left (e+f\,x\right )\right )}^m\,\left (a-a\,\sin \left (e+f\,x\right )\right ) \,d x \]
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